From: Steve Evans NETSPACE NET AU> Date: 21 feb 1999 Subject: Re: Repetition rule in Chu Shogi mating problems > Steve and I have been working on the D29 problem. > > I have finally come up with a superb 37-move mate (subject to Steve's > final checking) that solves this problem (and fully explains the role > of every piece in the problem). The only doubt I have, is that it > pre-supposes that the repetition rule for mating problems (at least in > the D document, or at least in D29), is that the DEFENDER must vary. > > What do people think of the plausibility of this being the intended > rule? > I have (with the aid of my program) just found the solution to this problem that does not require invocation the repetition rule (in any form). The problem D29 in the Middle Shogi Manual is as follows: 1, +BT, 9, +b / 12 / 1, FL, 10 / 12 / s, 11 / 12 / 6, +RC, 5 / l, 9, ky, 1 / R, 9, BT, 1 / 2, +RC, 8, +G / 3, GB, 1, r, 3, s, 1, K / 6, +rc, 3, +rc, +SM / The 38 move solution is: 1. +RC-2j, +Gx2j; 2. S-2l, Kx2l (if K-1i 3. S-1k mate.); 3. Kyx2j, K-3l; 4. R-3k, K-4l; 5. +RC-6j, +RCx6j (if K-5l see below for mating sequence) 6. Ky-4j, K-5l; 7. R-5k, K-6l; 8. Kyx6j, K-7l; 9. R-7k, K-8l; 10. Ky-8j, K-9l; 11. Rx9k, K-10l; 12. Kyx10j, K-11l 13. S-11d+, FLx11d 14. R-11k, K-12l 15. Ky-10l, +SMx10l 16. R-11i, K-12k (here, and throughout the rest of the problem, if +SM - 11k then +B x 11k mate) 17. +B-2a, K-12l (here, and throughout the rest of the problem, if K - 12j then +B - 11j mate) 18. +B-2b, K-12k 19. +B-3b, K-12l 20. +B-3c, K-12k 21. +B-4c, K-12l 22. +B-4d, K-12k 23. +B-5d, K-12l 24. +B-5e, K-12k 25. +B-6e, K-12l 26. +B-6f, K-12k 27. +B-7f, K-12l 28. +B-7g, K-12k 29. +B-8g, K-12l 30. +B-8h, K-12k 31. +B-9h, K-12l 32. +B-9i, K-12k 33. +B-10i, K-12l 34. +B-10j, K-12k 35. Rx12i, +SM-12j 36. Rx12j, Kx12j 37. L-12d+, FL-12e 38. +Lx12e mate. The alternative (switch-back) line from 5... is 5. .... K-5l; 6. R-5k, K-4l; 7. Ky-4j, K-3l; 8. R-3k, K-2l; 9. Ky-2j mate. This really is a brilliant problem, and worthy of the great Ito Kanju (if it is his). Many thanks to Colin Adams whose thoughts about continuing from move 17 with the slow advance of the +B at 1a, brought me back to this problem after I had written it off as insoluble. His assistance was invaluable. Colin's comments on some of the side-lines also appear above in brackets. Steve Evans