From: GRIMBERGEN PSYCH KUN NL Date: 22 nov 1990 Subject: Solutions old tsume Solutions Tsume Shogi October 24th 1) 1.+R4c Kx4c 2.B3c+ 2) 1.R'2b K3c 2.+B4c Kx4c 3.R4b+ 3) 1.S'1c Kx1c 2.B1d+ Rx1d 3.G'2c 4) 1.B2c+ Lx2c 2.+R1b Kx1b 3.B2b+ 5) 1.+R2c Gx2c 2.B'4c K2b 3.B'3a Kx3a 4.B(N)3b+ 6) 1.R'2c K1b 2.S'2a Kx2c 3.S3b= Kx3c 4.G'4c Solved by: Atkinson (1, 2, 3, 5) Blumberg (1, 3, 4, 5, 6) Reijer Grimbergen